Boundaries of hyperbolic components of Mandelbrot sets are closed curves : cardioids or circles.

Douady-Hubbard-Sullivan theorem (DHS) states that unit circle can be mapped to boundary of hyperbolic component. This relation is defined by boundary equations. Here these equations are used to draw boundaries of hyperbolic components.

The Douady-Hubbard-Sullivan theorem (DHS) states that the multiplier map ${\displaystyle \rho _{n}\,}$ of an attracting periodic orbit is a conformal isomorphism from a hyperbolic component ${\displaystyle H_{n}\,}$ of the Mandelbrot set onto the unit disk ${\displaystyle D\,}$ and it extends homeomorpically to the boundaries.^[2]

Here it is important that it maps the boundary of a hyperbolic component to the boundary of the unit disk ( = unit circle ) :

${\displaystyle \rho _{n}:\partial H_{n}\rightarrow \partial D\,}$

and its inverse function maps the unit circle to the boundary of hyperbolic components :

${\displaystyle \gamma _{n}:\partial D\rightarrow \partial H_{n}\,}$

The algorithm consist of

• rasterisation of a circle ( closed curve) parametrised by angle ${\displaystyle t\,}$
• complex mapping circle points to boundary points of a hyperbolic component

For given period ${\displaystyle n\,}$ do steps :

• Decide how many points of closed curve you want to draw ( iMax ).
• Compute ${\displaystyle dt={\frac {1}{iMax}}\,}$
• start with ${\displaystyle t=0\,}$
• while ${\displaystyle t<1\,}$ repeat :
  • compute point of the unit circle in the standard plane ${\displaystyle w=l(t)=e^{i*t}\,}$ where ${\displaystyle t\,}$ is an internal angle,
  • map points onto the parameter plane (complex mapping ) using one of 2 methods :
    • using explicit function ${\displaystyle c=\gamma _{n}(w)\,}$ ( it is possible only for periods 1-3)
    • solving implicit equation ${\displaystyle b_{n}(c,w)=0\,}$ with respect to ${\displaystyle c\,}$ ( it is posible for periods 1-8 using numerical methods)
  • compute new angle ${\displaystyle t=t+dt\,}$

• draw set of points, which looks like curve^[3]

Complex quadratic map :

f(z,c):=z*z+c;

Iterated function (map)  :

F(n, z, c) :=
   if n=1 then f(z,c)
   else f(F(n-1, z, c),c);

Multiplier of periodic orbit  :

${\displaystyle \lambda ={\frac {dF(n,z,c)}{dz}}\,}$

_lambda(n):=diff(F(n,z,c),z,1);

Unit circle ${\displaystyle \partial D\,}$ = boundary of unit disk

${\displaystyle \partial D=\left\{w:abs(w)=1\right\}}$

where coordinates of ${\displaystyle w\,}$ point of unit circle in exponential form are :

${\displaystyle w=e^{i*t}\,}$

Boundary equation

${\displaystyle b_{n}(w,c)=0\,}$

• defines relations between hyperbolic components and unit circle for given period ${\displaystyle n\,}$,
• allows computation of exact coordinates of hyperbolic componenets.

${\displaystyle b_{n}(w,c)\,}$ is boundary polynomial ( implicit function of 2 variables ).

Equations are in papers of Brown^[4],John Stephenson^[5], Wolf Jung^[6]. Methods of finding boundary equations are also described in WikiBooks.

For boundary points :

${\displaystyle P*2^{period}=w=e^{it}=\cos t+i*\sin t\,}$

so boundary equations can be in 4 equivalent forms :

period ${\displaystyle n\,}$	${\displaystyle b_{n}(P,c)=0\,}$	${\displaystyle b_{n}(w,c)=0\,}$	exponential ${\displaystyle b_{n}(t,c)=0\,}$	trigonometric ${\displaystyle b_{n}(t,c)=0\,}$
1	${\displaystyle c+P^{2}-P=0\,}$	${\displaystyle c+({\frac {w}{2}})^{2}-{\frac {w}{2}}=0\,}$	${\displaystyle c+({\frac {e^{it}}{2}})^{2}-{\frac {e^{it}}{2}}=0\,}$	${\displaystyle c+({\frac {\cos t+i*\sin t}{2}})^{2}-{\frac {\cos t+i*\sin t}{2}}=0\,}$
2	${\displaystyle -c+P-1=0\,}$	${\displaystyle -c+{\frac {w}{4}}-1=0\,}$	${\displaystyle -c+{\frac {e^{it}}{4}}-1=0\,}$	${\displaystyle -c+{\frac {\cos t+i*\sin t}{4}}-1=0\,}$

For higher periods only P-form is used, because it is the shortest and usefull for computations.

for period 3 :

${\displaystyle c^{3}+2*c^{2}-(P-1)*c+(P-1)^{2}=0\,}$

for period 4 :

${\displaystyle c^{6}+3*c^{5}+(P+3)*c^{4}+(P+3)*c^{3}-(P+2)*(P-1)*c^{2}-(P-1)^{3}=0\,}$

for period 5 :

${\displaystyle c^{15}+8c^{14}+28c^{13}+(P+60)c^{12}+(7P+94)c^{11}+(3P^{2}+20P+116)c^{10}+(11P^{2}+33P+114)c^{9}+(6P^{2}+40P+94)c^{8}+(2P^{3}-20P^{2}+37P+69)c^{7}+(3P-11)(3P^{2}-3P-4)c^{6}+(P-1)(3P^{3}+20P^{2}-33P-26)c^{5}+(3P^{2}+27P+14)(P-1)^{2}c^{4}-(6P+5)(P-1)^{3}c^{3}+(P+2)(P-1)^{4}c^{2}-c(P-1)^{5}+(P-1)^{6}=0\,}$

Boundary equations for periods:

• 1-3 it can be solved with symbolical methods and give explicit solution : ${\displaystyle c=\gamma _{n}(w)\,}$
  • 1-2 it is easy to solve^[7]
  • 3 it can be solve using "elementary algebra" ( Stephenson )
• >3 it can't be solved explicitly and must be solved numerically with respect to ${\displaystyle c\,}$.

There is only one period 1 component.^[8] Because boundary equation is simple :

${\displaystyle c+P^{2}-P=0\,}$

so it is easy to get inverse multiplier map :

${\displaystyle c=\gamma _{1}(P)=P-P^{2}\,}$

For each internal angle ${\displaystyle t\,}$ one computes :

• point on unit circle ${\displaystyle w=l(t)\,}$,
• ${\displaystyle P={\frac {w}{2}}\,}$
• point ${\displaystyle c=\gamma _{1}(P)\,}$

Result is a list of boundary points ${\displaystyle c\,}$ .

Because boundary equation is simple :

${\displaystyle -c+P-1=0\,}$

so it is easy to get inverse multiplier map  :

${\displaystyle c=\gamma _{2}(P)=P-1\,}$

For each internal angle ${\displaystyle t\,}$ one computes :

• point on unit circle ${\displaystyle w=l(t)\,}$,
• ${\displaystyle P={\frac {w}{2^{2}}}\,}$
• point ${\displaystyle c=\gamma _{2}(P)\,}$

Result is a list of boundary points ${\displaystyle c\,}$ .

There are 3 period 3 components^[9] Here solution of boundary equation gives 3 inverse multiplier maps ${\displaystyle c=\gamma _{3}(P)\,}$.

It is possible in 3 ways :

• Munafo method^[10] (every functions maps one half of one component and one half of other component)
• Giarrusso-Fisher method^[11] ( one function for one component )
• Walter Hannah method

I use functions by Robert Munafo.

(%i3) b3:c^3+2*c^2+(1-P)*c+(P-1)^2=0$
(%i4) solve(b3,c);
(%o4) [
c=(-(sqrt(3)*%i)/2-1/2)*(((P-1)*sqrt(27*P^2-22*P+23))/(6*sqrt(3))-(27*P^2-36*P+25)/54)^(1/3)+
(((sqrt(3)*%i)/2-1/2)*(3*P+1))/(9*(((P-  1)*sqrt(27*P^2-22*P+23))/(6*sqrt(3))-(27*P^2-36*P+25)/54)^(1/3))-2/3,
c=((sqrt(3)*%i)/2-1/2)*
(((P-1)*sqrt(27*P^2-22*P+23))/(6*sqrt(3))-(27*P^2-36*P+25)/54)^(1/3)+
((-(sqrt(3)*%i)/2-1/2)*(3*P+1))/(9*(((P-1)*sqrt(27*P^2-22*P+23)) /(6*sqrt(3))-
(27*P^2-36*P+25)/54)^(1/3))-2/3,
c=(((P-1)*sqrt(27*P^2-22*P+23))/(6*sqrt(3))-(27*P^2-36*P+25)/54)^(1/3)+
(3*P+1)/(9*(((P-1)*sqrt(27*P^2-22*P+23))/(6*sqrt(3))-(27*P^2-36*P+25)/54)^(1/3))

For each internal angle ${\displaystyle t\,}$ one computes :

• point on unit circle ${\displaystyle w=l(t)\,}$,
• ${\displaystyle P={\frac {w}{2^{3}}}\,}$
• points :
  • ${\displaystyle c=\gamma _{3a}(P)\,}$
  • ${\displaystyle c=\gamma _{3b}(P)\,}$
  • ${\displaystyle c=\gamma _{3c}(P)\,}$

Result is a list of boundary points ${\displaystyle c\,}$ .

Boundary equation ${\displaystyle b_{4}(P,c)=0\,}$ one can find in Mu-Ency. It can't be solved symbolicaly so it must be evaluated numerically^[12].

It is 1 equation with 2 variables. To solve it one has to compute ${\displaystyle P\,}$ and put in ${\displaystyle b_{4}(P,c)=0\,}$. Now it is equation with 1 variable ${\displaystyle c\,}$ and it can be solved numerically.

For each internal angle ${\displaystyle t\,}$ one computes :

• point on unit circle ${\displaystyle w=l(t)\,}$,
• ${\displaystyle P={\frac {w}{2^{4}}}\,}$
• Boundary polynomial ${\displaystyle b_{4}(P,c)\,}$
• solve boundary equation ${\displaystyle b_{4}(P,c)=0\,}$ with respect to ${\displaystyle c\,}$. Result is 6 roots ( each for one of 6 period 4 components).

Result is a list of boundary points ${\displaystyle c\,}$ .

b4(w):=c^6 + 3*c^5 + (w/16+3)* c^4 + (w/16+3)* c^3  - (w/16+2)* (w/16-1)* c^2 - (w/16-1)^3;
l(t):=%e^(%i*t*2*%pi);
iMax:200; /* number of point */
dt:1/iMax;
/* point to point method of drawing */
t:0; /* angle in turns */
w:rectform(ev(l(t), numer)); /* "exponential form prevents allroots from working", code by Robert P. Munafo */
/* compute equation for given w */
per4:expand(b4(w));
/* compute 6 complex roots and save them to the list cc4 */
cc4:allroots(per4);
/*  create new lists and save coordinates  to draw it later */ 
xx4:makelist (realpart(rhs(cc4[1])), i, 1, 1); 
yy4:makelist (imagpart(rhs(cc4[1])), i, 1, 1);
for j:2 thru 6 step 1 do
 block
 (
  xx4:cons(realpart(rhs(cc4[j])),xx4),
  yy4:cons(imagpart(rhs(cc4[j])),yy4)
 );
for i:2 thru iMax step 1 do
block
( t:t+dt,
  w:rectform(ev(l(t), numer)), /* code by Robert P. Munafo  */
  per4:expand(m4(w)),
  cc4:allroots(per4),
  for j:1 thru 6 step 1 do
   block
   (
    xx4:cons(realpart(rhs(cc4[j])),xx4),
    yy4:cons(imagpart(rhs(cc4[j])),yy4)
   )
  );

one computes in the same way as for period 4, only implicit function is different and there are 15 components.

one computes in the same way as for period 4, only implicit function is different (see Stephenson paper II ) and there are 27 components.

one computes in the same way as for period 4, only implicit function is different (degree in c is 63; see Stephenson paper III ) and there are 63 components.

Implicit equation ${\displaystyle b_{8}(P,c)=0\,}$ can be computed but "is too large to exhibit" (see Stephenson paper III ). There are 120 components.

"Although extension of the arithmethic method to higher orders is possible in principle, the computations become too big in space and time" (Stephenson paper III )

period ${\displaystyle n\,}$	${\displaystyle b_{n}(P,c)=0\,}$	${\displaystyle P=\rho _{n}(c)\,}$	${\displaystyle c=\gamma _{n}(P)\,}$	${\displaystyle \lambda _{c,n}(z)={\frac {dF(n,z,c)}{dz}}\,}$
1	${\displaystyle c+P^{2}-P=0\,}$	${\displaystyle P=1-{\sqrt {1-4c}}\,}$	${\displaystyle c=P-P^{2}\,}$	${\displaystyle \lambda _{c,1}(z)=2z\,}$
2	${\displaystyle -c+P-1=0\,}$	${\displaystyle P=c+1\,}$	${\displaystyle c=P-1\,}$	${\displaystyle \lambda _{c,2}(z)=4z^{3}+4cz\,}$
3	${\displaystyle c^{3}+2c^{2}-(P-1)c+(P-1)^{2}=0\,}$			${\displaystyle \lambda _{c,3}(z)=8z^{7}+24cz^{5}+(24c^{2}+8c)z^{3}+(8c^{3}+8c^{2})z\,}$

Symbolic solution of boundary equation is possible only for periods 1-3 ( with respect to ${\displaystyle P\,}$ or ${\displaystyle c\,}$). Every function can be in 4 equivalent forms : P, w, exponential t, trigonometric t (see boundary equations for details).

Solving with respect to ${\displaystyle P\,}$ gives 2 results. One choose attracting

Solving is simple because these are degree 1 equations ( with respect to both ${\displaystyle P\,}$ and ${\displaystyle c\,}$).

Solving with respect to ${\displaystyle c\,}$ is possible in 3 ways.

Solving with respect to ${\displaystyle P\,}$ gives 2 results. One have to choose attracting.

/* 
batch file for Maxima
http://maxima.sourceforge.net/
wxMaxima 0.7.6 http://wxmaxima.sourceforge.net archive copy at the Wayback Machine
Maxima 5.16.1 http://maxima.sourceforge.net
Using Lisp GNU Common Lisp (GCL) GCL 2.6.8 (aka GCL)
Distributed under the GNU Public License. 
based on :
http://www.mrob.com/pub/muency/brownmethod.html
*/
start:elapsed_run_time ();
iMax:200; /* number of points to draw */
dt:1/iMax;
/* 
unit circle D={w:abs(w)=1 } where w=l(t) 
t is angle in turns ; 1 turn = 360 degree = 2*Pi radians 
*/
l(t):=%e^(%i*t*2*%pi);
/* 
conformal maps from unit circle 
to hyperbolic component of Mandelbrot set of period 1-4 
These functions ( maps ) are computed in other batch file 
*/
/* ---------------  inverse function of multiplier map : explicit function : c=gamma_p(P)  where P = w/(2^period) ---------------- */
gamma1(P):=P-P^2;
gamma2(P):=P - 1;
gamma3a(P):=(-(sqrt(3)*%i)/2-1/2)*(((P-1)*sqrt(27*P^2-22*P+23))/(6*sqrt(3))-(27*P^2-36*P+25)/54)^(1/3)+
(((sqrt(3)*%i)/2-1/2)*(3*P+1))/(9*(((P-1)*sqrt(27*P^2-22*P+23))/(6*sqrt(3))-(27*P^2-36*P+25)/54)^(1/3))-2/3;
gamma3b(P):=((sqrt(3)*%i)/2-1/2)*(((P-1)*sqrt(27*P^2-22*P+23))/(6*sqrt(3))-(27*P^2-36*P+25)/54)^(1/3)+
((-(sqrt(3)*%i)/2-1/2)*(3*P+1))/(9*(((P- 1)*sqrt(27*P^2-22*P+23))/(6*sqrt(3))-(27*P^2-36*P+25)/54)^(1/3))-2/3;
gamma3c(P):=(((P-1)*sqrt(27*P^2-22*P+23))/(6*sqrt(3))-(27*P^2-36*P+25)/54)^(1/3)+(3*P+1)/(9*(((P-1)*sqrt(27*P^2-22*P+23))/(6*sqrt(3))-
(27*P^2-36*P+25) /54)^(1/3))-2/3;
/* ---------- boundary equation (implicit function)  b_p(P,c)=0 ------------------------------------------------------------------ */
b4(P):=c^6 + 3*c^5 + (P+3)* c^4 + (P+3)* c^3  - (P+2)*(P-1)*c^2 - (P-1)^3;
/* ------ period 5 ------------- */
b5(P):=c^15 + 
8*c^14 + 
28*c^13 + 
(P + 60)*c^12 + 
(7*P + 94)*c^11 + 
(3*(P)^2 + 20*P + 116)*c^10 + 
(11*P^2 + 33*P + 114)*c^9 +
(6*P^2 + 40*P + 94)*c^8 + 
(2*P^3 - 20*P^2 + 37*P + 69)*c^7 + 
(3*P - 11)*(3*P^2 - 3*P - 4)*c^6 + 
(P - 1)*(3*P^3 + 20*P^2 - 33*P - 26)*c^5 + 
(3*P^2 + 27*P + 14)*((P - 1)^2)*c^4 - 
(6*P + 5)*((P - 1)^3 )*c^3 + 
(P + 2)*((P - 1)^4)*c^2 - 
c*(P - 1)^5  + 
(P - 1)^6 ;
/*-----period 6 ----------------------- */
b6(P):=
c^27+
13*c^26+
78*c^25+
(293 - P)*c^24+
(792 - 10*P)*c^23+
(1672 - 41*P)*c^22+
(2892 - 84*P - 4*P^2)*c^21+
(4219 - 60*P - 30*P^2)*c^20+
(5313 + 155*P - 80*P^2)*c^19+
(5892 + 642*P - 57*P^2 + 4*P^3)*c^18+
(5843 + 1347*P + 195*P^2 + 22*P^3)*c^17+
(5258 + 2036*P + 734*P^2 + 22*P^3)*c^16+
(4346 + 2455*P + 1441*P^2 - 112*P^3 + 6*P^4)*c^15 + 
(3310 + 2522*P + 1941*P^2 - 441*P^3 + 20*P^4)*c^14 + 
(2331 + 2272*P + 1881*P^2 - 853*P^3 - 15*P^4)*c^13 + 
(1525 + 1842*P + 1344*P^2 - 1157*P^3 - 124*P^4 - 6*P^5)*c^12 + 
(927 + 1385*P + 570*P^2 - 1143*P^3 - 189*P^4 - 14*P^5)*c^11 + 
(536 + 923*P - 126*P^2 - 774*P^3 - 186*P^4 + 11*P^5)*c^10 + 
(298 + 834*P + 367*P^2 + 45*P^3 - 4*P^4 + 4*P^5)*(1-P)*c^9 + 
(155 + 445*P - 148*P^2 - 109*P^3 + 103*P^4 + 2*P^5)*(1-P)*c^8 + 
2*(38 + 142*P - 37*P^2 - 62*P^3 + 17*P^4)*(1-P)^2*c^7 + 
(35 + 166*P + 18*P^2 - 75*P^3 - 4*P^4)*((1-P)^3)*c^6 + 
(17 + 94*P + 62*P^2 + 2*P^3)*((1-P)^4)*c^5 + 
(7 + 34*P + 8*P^2)*((1-P)^5)*c^4 + 
(3 + 10*P + P^2)*((1-P)^6)*c^3 + 
(1 + P)*((1-P)^7)*c^2 +
-c*((1-P)^8) + (1-P)^9;
/*-----------------------------------*/
/* point to point method of drawing */
t:0; /* angle in turns */ 
/* compute first point of curve, create list and save point to this list */
/* point of unit circle   w:l(t); */
w:rectform(ev(l(t), numer)); /* "exponential form prevents allroots from working", code by Robert P. Munafo */ 
/* ---- period 1 -------------------*/
P:w/2;
c1:gamma1(P);
xx1:makelist (realpart(c1), i, 1, 1); /* save coordinates  to draw it later */ 
yy1:makelist (imagpart(c1), i, 1, 1);
/* -----period 2 --------------*/
P:P/2;
c2:gamma2(P); 
xx2:makelist (realpart(c2), i, 1, 1); 
yy2:makelist (imagpart(c2), i, 1, 1); 
/* period 3 components */
P:P/2;
c3:gamma3a(P); 
xx3a:makelist (realpart(c3), i, 1, 1); 
yy3a:makelist (imagpart(c3), i, 1, 1); 
c3:gamma3b(w);
xx3b:makelist (realpart(c3), i, 1, 1); 
yy3b:makelist (imagpart(c3), i, 1, 1); 
c3:gamma3c(w);
xx3c:makelist (realpart(c3), i, 1, 1); 
yy3c:makelist (imagpart(c3), i, 1, 1);
/* period 4 */ 
P:P/2;
per4:expand(b4(P)); /* compute equation for given w ( t) */
cc4:allroots(per4); /* compute 6 complex roots and save them to the list cc4 */
/*  create new lists and save coordinates  to draw it later */ 
xx4:makelist (realpart(rhs(cc4[1])), i, 1, 1); 
yy4:makelist (imagpart(rhs(cc4[1])), i, 1, 1);
for j:2 thru 6 step 1 do
block
(
 xx4:cons(realpart(rhs(cc4[j])),xx4),
 yy4:cons(imagpart(rhs(cc4[j])),yy4)
);
/* period 5 */
P:P/2;
per5:expand(b5(P)); /* compute equation for given w ( t) */
cc5:allroots(per5); /* compute 15 complex roots and save them to the list cc5 */
/*  create new lists and save coordinates  to draw it later */ 
xx5:makelist (realpart(rhs(cc5[1])), i, 1, 1); 
yy5:makelist (imagpart(rhs(cc5[1])), i, 1, 1);
for j:2 thru 15 step 1 do
block
(
xx5:cons(realpart(rhs(cc5[j])),xx5),
yy5:cons(imagpart(rhs(cc5[j])),yy5)
);
/* period 6 */
P:P/2;
per6:expand(b6(P)); /* compute equation for given w ( t) */
cc6:allroots(per6); /* compute 15 complex roots and save them to the list cc5 */
/*  create new lists and save coordinates  to draw it later */ 
xx6:makelist (realpart(rhs(cc6[1])), i, 1, 1); 
yy6:makelist (imagpart(rhs(cc6[1])), i, 1, 1);
for j:2 thru 27 step 1 do
block
(
xx6:cons(realpart(rhs(cc6[j])),xx6),
yy6:cons(imagpart(rhs(cc6[j])),yy6)
);
/* ------------*/
for i:2 thru iMax step 1 do
block
( t:t+dt,
 w:rectform(ev(l(t), numer)), /* "exponential form prevents allroots from working", code by Robert P. Munafo */ 
 P:w/2,
 c1:gamma1(P),
 /* save values to draw it later */
 xx1:cons(realpart(c1),xx1),
 yy1:cons(imagpart(c1),yy1),
 P:P/2,
 c2:gamma2(P),
 xx2:cons(realpart(c2),xx2),
 yy2:cons(imagpart(c2),yy2),
 P:P/2,
 c3:gamma3a(P),
 xx3a:cons(realpart(c3),xx3a),
 yy3a:cons(imagpart(c3),yy3a),
 c3:gamma3b(P),
 xx3b:cons(realpart(c3),xx3b),
 yy3b:cons(imagpart(c3),yy3b),
 c3:gamma3c(P),
 xx3c:cons(realpart(c3),xx3c),
 yy3c:cons(imagpart(c3),yy3c),
 /* period 4 */
 P:P/2,
 per4:expand(b4(P)),
 cc4:allroots(per4),
 for j:1 thru 6 step 1 do
  block
   (
   xx4:cons(realpart(rhs(cc4[j])),xx4),
   yy4:cons(imagpart(rhs(cc4[j])),yy4)
   ),
 /* period 5 */
 P:P/2,
 per5:expand(b5(P)), /* compute equation for given w ( t) */
 cc5:allroots(per5), /* compute 15 complex roots and save them to the list cc5 */
 for j:1 thru 15 step 1 do
 block
  (
  xx5:cons(realpart(rhs(cc5[j])),xx5),
  yy5:cons(imagpart(rhs(cc5[j])),yy5)
  ),
 /* period 6 */
 P:P/2,
 per6:expand(b6(P)), /* compute equation for given w ( t) */
 cc6:allroots(per6), /* compute 27 complex roots and save them to the list cc6 */
 for j:1 thru 27 step 1 do
  block
  (
  xx6:cons(realpart(rhs(cc6[j])),xx6),
  yy6:cons(imagpart(rhs(cc6[j])),yy6)
  )    
 );
stop:elapsed_run_time ();
time:fix(stop-start); 
load(draw);
draw2d(
 user_preamble="set terminal svg size 1000,1000;set out 'mysvg2.svg';set size square;set key out vert;set key bot center",
  pic_width  = 1000,
  pic_height = 1000,
  yrange = [-1.5,1.5],
  xrange = [-2,1],
  title= concat("Boundaries of 53 hyperbolic components of Mandelbrot set made in ",string(time),"sec"),
  xlabel     = "c.re ",
  ylabel     = "c.im",
  point_type    = dot,
  point_size    = 5,
  points_joined =true,
  key = "one period 1 component = {c:c=(2*w-w*w)/4} ",
  color         = red,
  points(xx1,yy1),
  key = "one period 2 component = {c:c=(w/4 -1)} ",
  color         = green,
  points(xx2,yy2),
  key = "",
  color         = red,
  points_joined =false, /* there are 3 curves so we can't join points */
  points(xx3a,yy3a),
  points(xx3b,yy3b),
  key = "three period 3 components (blue)",
  points(xx3c,yy3c),
  key = "six period 4 components (magenta)",
  color         = red,
  points(xx4,yy4),
  key = "fifteen period 5 components (black)",
  color         = red,
  points(xx5,yy5),
  key = "27 period 6 components (black)",
  color         = red,
  points(xx6,yy6)
);

1. ↑ Mario Rodriguez proposition in discussion about discrete dynamical system on the Maxima mailing list
2. ↑ Multipliers of periodic orbits of quadratic polynomials and the parameter plane by Genadi Levin
3. ↑ Algebraic solution of Mandelbrot orbital boundaries by Donald D. Cross
4. ↑ A. Brown, Equations for Periodic Solutions of a Logistic Difference Equation, J. Austral. Math. Soc (Series B) 23, 78–94 (1981).
5. ↑ John Stephenson : "Formulae for cycles in the Mandelbrot set", Physica A 177, 416-420 (1991); "Formulae for cycles in the Mandelbrot set II", Physica A 190, 104-116 (1992); "Formulae for cycles in the Mandelbrot set III", Physica A 190, 117-129 (1992)
6. ↑ Wolf Jung : "Some Explicit Formulas for the Iteration of Rational Functions" , unpublished manuscript of August 1997 containing Maple code
7. ↑ Thayer Watkins : The Structure of the Mandelbrot Set
8. ↑ Enumeration of Features by Robert P. Munafo
9. ↑ M. Lutzky: Counting hyperbolic components of the Mandelbrot set. Physics Letters A Volume 177, Issues 4-5, 21 June 1993, Pages 338-340
10. ↑ Brown Method by Robert P. Munafo
11. ↑ A Parameterization of the Period 3 Hyperbolic Components of the Mandelbrot Set Dante Giarrusso; Yuval Fisher Proceedings of the American Mathematical Society, Vol. 123, No. 12. (Dec., 1995), pp. 3731-3737
12. ↑ Exact Coordinates by Robert P. Munafo

• Newsgroups: gmane.comp.mathematics.maxima.general Subject: polynomial equations Date: 2007-09-26

This program is not only my work but was done with help of many great people (see references). Warm thanks (:-))

Aquest fitxer està subjecte a la llicència de Creative Commons Reconeixement i Compartir Igual 3.0 No adaptada.

Sou lliure de:

• compartir – copiar, distribuir i comunicar públicament l'obra
• adaptar – fer-ne obres derivades

Amb les condicions següents:

• reconeixement – Heu de donar la informació adequada sobre l'autor, proporcionar un enllaç a la llicència i indicar si s'han realitzat canvis. Podeu fer-ho amb qualsevol mitjà raonable, però de cap manera no suggereixi que l'autor us dóna suport o aprova l'ús que en feu.
• compartir igual – Si modifiqueu, transformeu, o generareu amb el material, haureu de distribuir les vostres contribucions sota una llicència similar o una de compatible com l'original

https://creativecommons.org/licenses/by-sa/3.0CC BY-SA 3.0 Creative Commons Attribution-Share Alike 3.0 truetrue

 

Aquesta imatge vectorial ha estat creada amb Gnuplot.

 

W3C-validity not checked.